In a tug-of-war,one team gives way to the other. What work is being done and by whom?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) In a tug-of-war,the winning team exerts a force on the losing team,causing them to move in the direction of the force.
Since the force applied by the winning team and the displacement of the losing team are in the same direction,the winning team performs positive work.
The magnitude of the work done is equal to the product of the resultant force applied by the winning team and the displacement undergone by the losing team.

Explore More

Similar Questions

State whether the following statement is true or false:
The rate of doing work is called power.

$A$ body moves along a circular path. How much work is done in doing so? Explain.

$(a)$ State the law of conservation of energy.
$(b)$ What is the work done to increase the velocity of a car from $36 \, km/h$ to $72 \, km/h$ if the mass of the car is $1500 \, kg$? Does the work done by the force have a negative or a positive magnitude?
$(c)$ Where does an oscillating pendulum have maximum potential energy $(PE)$ and kinetic energy $(KE)$?

Does work done depend upon the velocity of the body?

What happens to the kinetic energy when
$(i)$ the mass of the body is doubled at constant velocity?
$(ii)$ the velocity of the body is doubled at constant mass?
$(iii)$ the mass of the body is doubled but the velocity is reduced to half?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo