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Question

(D) Magnesium $(Mg)$ is an active metal that reacts with dilute acids to liberate hydrogen gas $(H_2)$.$1$. Reaction with dilute $HCl$: $Mg + 2HCl \ri

Vedclass · Accepted Answer

all of these

Vedclass · Answer

(D) Magnesium $(Mg)$ is an active metal that reacts with dilute acids to liberate hydrogen gas $(H_2)$.$1$. Reaction with dilute $HCl$: $Mg + 2HCl \rightarrow MgCl_2 + H_2 \uparrow$$2$. Reaction with dilute $H_2SO_4$: $Mg + H_2SO_4 \rightarrow MgSO_4 + H_2 \uparrow$$3$. Reaction with very dilute $HNO_3$: $Mg + 2HNO_3 \rightarrow Mg(NO_3)_2 + H_2 \uparrow$Since $Mg$ reacts with all these dilute acids to produce $H_2$ gas,the correct option is $D$.

Magnesium liberates $H_2$ gas on reaction with

Similar Questions

Starting with sodium chloride,how would you proceed to prepare:
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