Magnesium reacts with an element (X) to form | vedclass

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(D) The electronic configuration of element $(X)$ is $1s^{2} 2s^{2} 2p^{3}$.This corresponds to Nitrogen $(N)$,which has $5$ valence electrons and nee

Vedclass · Accepted Answer

$Mg_{3}X_{2}$

Vedclass · Answer

(D) The electronic configuration of element $(X)$ is $1s^{2} 2s^{2} 2p^{3}$.This corresponds to Nitrogen $(N)$,which has $5$ valence electrons and needs $3$ electrons to complete its octet,forming an ion with a charge of $-3$ $(N^{3-})$.Magnesium $(Mg)$ is an alkaline earth metal with $2$ valence electrons,forming an ion with a charge of $+2$ $(Mg^{2+})$.To form a neutral ionic compound,the charges must balance: $3 	imes (+2) + 2 	imes (-3) = 0$.Therefore,the simplest formula for the compound is $Mg_{3}X_{2}$.

Magnesium reacts with an element $(X)$ to form an ionic compound. If the ground state electronic configuration of $(X)$ is $1s^{2} 2s^{2} 2p^{3},$ the simplest formula for this compound is

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