The magnetic moment of the complexes is zero | vedclass

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Question

(A) For a complex to have a magnetic moment of zero,it must be diamagnetic (no unpaired electrons).$1$. In $[Ni(CN)_4]^{2-}$,$Ni$ is in the $+2$ oxida

Vedclass · Accepted Answer

$[Ni(CN)_4]^{2-} , [Ni(CO)_4]$

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(A) For a complex to have a magnetic moment of zero,it must be diamagnetic (no unpaired electrons).$1$. In $[Ni(CN)_4]^{2-}$,$Ni$ is in the $+2$ oxidation state $(3d^8)$. $CN^-$ is a strong field ligand,causing pairing of electrons,resulting in $0$ unpaired electrons.$2$. In $[Ni(CO)_4]$,$Ni$ is in the $0$ oxidation state $(3d^8 4s^2)$. $CO$ is a strong field ligand,causing pairing of electrons,resulting in $0$ unpaired electrons.Both complexes are diamagnetic,so $\mu_s = 0$.

The magnetic moment of the complexes is zero in:

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