Major product of the reaction is :

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Question

(D) The reaction involves the ionization of the tosylate group $(-OTs)$ to form a carbocation. Due to the presence of the phenyl group,a phenonium ion

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$(CH_3)_2C=C(^{14}CH_3)Ph$

Vedclass · Answer

(D) The reaction involves the ionization of the tosylate group $(-OTs)$ to form a carbocation. Due to the presence of the phenyl group,a phenonium ion intermediate is formed via the migration of the phenyl group to the $^{14}C$ atom. This rearrangement leads to the formation of a more stable carbocation. Finally,the loss of a proton $(-H^+)$ results in the formation of the alkene. The $^{14}C$ label remains at the carbon attached to the phenyl group in the final product,which is $(CH_3)_2C=C(^{14}CH_3)Ph$.

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