The major product of the reaction is:

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(A) The reaction is an $E_2$ elimination reaction. In $E_2$ reactions,the leaving group $(-OTs)$ and the $\beta$-hydrogen must be in an anti-periplana

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$1-$methylcyclohexene

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(A) The reaction is an $E_2$ elimination reaction. In $E_2$ reactions,the leaving group $(-OTs)$ and the $\beta$-hydrogen must be in an anti-periplanar conformation to undergo elimination. In the given substrate,the $-OTs$ group is in the equatorial position. For anti-elimination,the $\beta$-hydrogen must be anti to the $-OTs$ group. The hydrogen at the $C_1$ position (bearing the $-CH_3$ group) is anti to the $-OTs$ group. Therefore,the base abstracts this proton,leading to the formation of the double bond between $C_1$ and $C_2$,resulting in $1$-methylcyclohexene as the major product.

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