The major product of the reaction is:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction is an iodolactonization. $1$. The $I_2$ reacts with the alkene to form a cyclic iodonium ion intermediate. $2$. The $NaHCO_3$ acts as

Vedclass · Accepted Answer

Vedclass · Answer

(B) The reaction is an iodolactonization. $1$. The $I_2$ reacts with the alkene to form a cyclic iodonium ion intermediate. $2$. The $NaHCO_3$ acts as a base to deprotonate the carboxylic acid group,forming a carboxylate ion. $3$. The carboxylate oxygen performs an intramolecular nucleophilic attack on the more substituted carbon of the iodonium ion,leading to the formation of a five-membered lactone ring. $4$. The final product is an iodolactone,where the iodine atom and the oxygen atom are added across the double bond in an anti-fashion. Based on the structure,the correct product is the one where the iodine is at the bridgehead position and the lactone ring is fused to the cyclohexane ring.

Similar Questions

The correct statement is

The product$(s)$ from the above reaction will be

The end product formed in the above reaction is:

The product of the above reaction will be:

Product $(A)$ of the reaction is

Vedclass Test Series

Exam Paper Generator

Online Exam Module