Major product of the reaction is

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(A) The reaction involves the hydrolysis of a thioester and an ester group using $HO^-$ followed by $H^+$.$1.$ The hydroxide ion $(HO^-)$ acts as a nu

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(A) The reaction involves the hydrolysis of a thioester and an ester group using $HO^-$ followed by $H^+$.$1.$ The hydroxide ion $(HO^-)$ acts as a nucleophile and attacks the carbonyl carbon of the thioester group,leading to the formation of a thiolate anion $(S^-)$ and an acetate ion.$2.$ The hydroxide ion also attacks the carbonyl carbon of the ester group,leading to the formation of an alkoxide ion $(O^-)$ and another acetate ion.$3.$ Upon workup with $H^+$,the thiolate anion is protonated to form a thiol $(-SH)$ and the alkoxide ion is protonated to form an alcohol $(-OH)$.$4.$ Since the starting material has both groups in a cis-configuration (both are wedged),the final product retains this stereochemistry,resulting in a cis-hydroxy thiol.

Column-$I$ (Reactants)	Column-$II$ (Products)
$A$. Cumene $+ O_2$	$i$. Phenol
$B$. Benzene sulphonic acid $\xrightarrow{NaOH, H^+}$	$ii$. $2$-Methylbutan-$1$-ol
$C$. Chlorobenzene $+ NaOH \xrightarrow{623 \ K, 300 \ atm}$	$iii$. Cumene hydroperoxide
$D$. $2$-Methylbutanal $\xrightarrow{NaBH_4}$	$iv$. Sodium phenoxide

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