What is the major product of this reaction?

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(A) The reaction between benzaldehyde $(Ph-CHO)$ and two equivalents of benzene $(C_6H_6)$ in the presence of concentrated sulfuric acid $(H_2SO_4)$ i

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$Ph_3CH$

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(A) The reaction between benzaldehyde $(Ph-CHO)$ and two equivalents of benzene $(C_6H_6)$ in the presence of concentrated sulfuric acid $(H_2SO_4)$ is an electrophilic aromatic substitution reaction. $1$. The acid protonates the carbonyl oxygen of benzaldehyde to form a highly reactive electrophilic carbocation intermediate $(Ph-CH^{+}-OH)$. $2$. This electrophile undergoes electrophilic aromatic substitution with the first molecule of benzene to form diphenylmethanol $(Ph_2CHOH)$. $3$. In the presence of acid,the hydroxyl group is protonated and leaves as water,generating a stable diphenylmethyl carbocation $(Ph_2CH^{+})$. $4$. This carbocation then undergoes a second electrophilic aromatic substitution with the second molecule of benzene to yield triphenylmethane $(Ph_3CH)$ as the major product.

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