The major product(s) of the reaction is (are) | vedclass

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(D) $1$. Cyclopentadiene reacts with $KH$ to form the cyclopentadienyl anion,which is aromatic.$2$. The cyclopentadienyl anion has resonance structure

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Both $b$ and $c$.

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(D) $1$. Cyclopentadiene reacts with $KH$ to form the cyclopentadienyl anion,which is aromatic.$2$. The cyclopentadienyl anion has resonance structures where the negative charge is delocalized over all five carbon atoms.$3$. When this anion is treated with $H_2O$ (a proton source),the proton can add to any of the carbon atoms that carry the negative charge in the resonance hybrid.$4$. Due to the symmetry of the cyclopentadienyl anion,the label (marked as $C^{14}$) can end up at different positions relative to the double bonds in the final product.$5$. The resonance structures show that the negative charge is distributed such that the protonation results in a mixture of isomers where the label is at different positions.$6$. Based on the resonance hybrid and the statistical distribution,the products $b$ and $c$ are formed as major products.

The major product$(s)$ of the reaction is (are):

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