Masses of three wires of copper are in the ratio of $1 : 3 : 5$ and their lengths are in the ratio of $5 : 3 : 1$. The ratio of their electrical resistance is . . . . . . .

  • A
    $5: 3: 1$
  • B
    $\sqrt{125}: 15: 1$
  • C
    $1: 15: 125$
  • D
    $1: 3: 5$

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