Match column-$I$ and column-$II$ with correct relation:
Column-$I$ Column-$II$
$(i)$ Blood like red colour $(a)$ $Fe_4[Fe(CN)_6]_3$
$(ii)$ Sodium nitroprusside $(b)$ $(NH_4)_2MoO_4$
$(iii)$ Ammonium molybdate $(c)$ $[Fe(SCN)]^{2+}$
$(iv)$ Ferri-ferro cyanide $(d)$ $Na_2[Fe(CN)_5NO]$

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) The correct matches are:
$(i)$ Blood like red colour is due to the formation of the complex $[Fe(SCN)]^{2+}$,which corresponds to $(c)$.
$(ii)$ Sodium nitroprusside is the chemical compound $Na_2[Fe(CN)_5NO]$,which corresponds to $(d)$.
$(iii)$ Ammonium molybdate is $(NH_4)_2MoO_4$,which corresponds to $(b)$.
$(iv)$ Ferri-ferro cyanide is $Fe_4[Fe(CN)_6]_3$,which corresponds to $(a)$.
Therefore,the correct matching is $(i-c), (ii-d), (iii-b), (iv-a)$.

Explore More

Similar Questions

How do we differentiate between $Fe^{3+}$ and $Cr^{3+}$ in group $III$?

$A$ solution,when diluted with $H_2O$ and boiled,gives a white precipitate. On the addition of excess $NH_4Cl / NH_4OH$,the volume of the precipitate decreases,leaving behind a white gelatinous precipitate. Identify the precipitate which dissolves in $NH_4OH / NH_4Cl$.

The solution of $BiCl_{3}$ in dil. $HCl$ when diluted with water,forms a white precipitate which is:

Which of the following gives a black precipitate when $H_2S$ gas is passed through its solution?

Which one among the following pairs of ions cannot be separated by $H_2S$ in dilute hydrochloric acid?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo