Match List-I with List-II :List-IList-IIa. NH | vedclass

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Question

(B) $NH_3$: $sp^3$ hybridization with $1$ lone pair $(LP)$ results in a Trigonal pyramidal geometry $(a-iii)$.$ClF_3$: $sp^3d$ hybridization with $2$

Vedclass · Accepted Answer

$a-iii, b-iv, c-ii, d-i$

Vedclass · Answer

(B) $NH_3$: $sp^3$ hybridization with $1$ lone pair $(LP)$ results in a Trigonal pyramidal geometry $(a-iii)$.$ClF_3$: $sp^3d$ hybridization with $2$ lone pairs $(LP)$ results in a $T$-shape geometry $(b-iv)$.$PCl_5$: $sp^3d$ hybridization with $0$ lone pairs $(LP)$ results in a Trigonal bipyramidal geometry $(c-ii)$.$BrF_5$: $sp^3d^2$ hybridization with $1$ lone pair $(LP)$ results in a Square pyramidal geometry $(d-i)$.Therefore,the correct matching is $a-iii, b-iv, c-ii, d-i$.

List-$I$	List-$II$
$a. NH_3$	$i$. Square pyramidal
$b. ClF_3$	$ii$. Trigonal bipyramidal
$c. PCl_5$	$iii$. Trigonal pyramidal
$d. BrF_5$	$iv$. $T$-shape

Molecule	Geometry
$(a) SnCl_2$	$(i)$ Angular (or) Bent
$(b) XeF_4$	$(ii)$ See-saw
$(c) ClF_3$	$(iii)$ Square pyramidal
$(d) IF_5$	$(iv)$ $T$-shape
-	$(v)$ Square planar

Match List-$I$ with List-$II$ :
List-$I$ List-$II$
$a. NH_3$ $i$. Square pyramidal
$b. ClF_3$ $ii$. Trigonal bipyramidal
$c. PCl_5$ $iii$. Trigonal pyramidal
$d. BrF_5$ $iv$. $T$-shape

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Similar Questions

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Molecule Geometry
$(a) SnCl_2$ $(i)$ Angular (or) Bent
$(b) XeF_4$ $(ii)$ See-saw
$(c) ClF_3$ $(iii)$ Square pyramidal
$(d) IF_5$ $(iv)$ $T$-shape
- $(v)$ Square planar

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$SbF_5$ reacts with $XeF_4$ and $XeF_6$ to form ionic compounds $[XeF_3^+][SbF_6^-]$ and $[XeF_5^+][SbF_6^-]$. Determine the molecular shape of $[XeF_3^+]$ ion and $[XeF_5^+]$ ion respectively.

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Match List-$I$ with List-$II$ :List-$I$List-$II$$a. NH_3$$i$. Square pyramidal$b. ClF_3$$ii$. Trigonal bipyramidal$c. PCl_5$$iii$. Trigonal pyramidal$d. BrF_5$$iv$. $T$-shapeChoose the correct answer from the options given below :