Match List I with List II:List IList IIA. Spr | vedclass

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(A) $1$. Spring constant $(k)$: $F = kx \implies [k] = [F]/[x] = (MLT^{-2}) / L = MT^{-2}$. Thus,$A-II$.$2$. Angular speed $(\omega)$: $\omega = \Delt

Vedclass · Accepted Answer

$(A)-(II), (B)-(I), (C)-(IV), (D)-(III)$

Vedclass · Answer

(A) $1$. Spring constant $(k)$: $F = kx \implies [k] = [F]/[x] = (MLT^{-2}) / L = MT^{-2}$. Thus,$A-II$.$2$. Angular speed $(\omega)$: $\omega = \Delta	heta / \Delta t \implies [\omega] = [1] / T = T^{-1}$. Thus,$B-I$.$3$. Angular momentum $(L)$: $L = mvr \implies [L] = M(LT^{-1})L = ML^2T^{-1}$. Thus,$C-IV$.$4$. Moment of inertia $(I)$: $I = mr^2 \implies [I] = ML^2$. Thus,$D-III$.Therefore,the correct matching is $(A)-(II), (B)-(I), (C)-(IV), (D)-(III)$.

List $I$	List $II$
$A$. Spring constant	$I$. $(T^{-1})$
$B$. Angular speed	$II$. $(MT^{-2})$
$C$. Angular momentum	$III$. $(ML^2)$
$D$. Moment of inertia	$IV$. $(ML^2T^{-1})$

Match List $I$ with List $II$:
List $I$ List $II$
$A$. Spring constant $I$. $(T^{-1})$
$B$. Angular speed $II$. $(MT^{-2})$
$C$. Angular momentum $III$. $(ML^2)$
$D$. Moment of inertia $IV$. $(ML^2T^{-1})$

Choose the correct answer from the options given below:

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Match List $I$ with List $II$:List $I$List $II$$A$. Spring constant$I$. $(T^{-1})$$B$. Angular speed$II$. $(MT^{-2})$$C$. Angular momentum$III$. $(ML^2)$$D$. Moment of inertia$IV$. $(ML^2T^{-1})$Choose the correct answer from the options given below: