Match List-I with List-II.Choose the correct | vedclass

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(D) The reactions are matched as follows:$(A)$ Aniline reacts with $NaNO_2 + HCl$ followed by warm $H_2O$ to form phenol. This corresponds to product

Vedclass · Accepted Answer

$A-II, B-IV, C-I, D-III$

Vedclass · Answer

(D) The reactions are matched as follows:$(A)$ Aniline reacts with $NaNO_2 + HCl$ followed by warm $H_2O$ to form phenol. This corresponds to product $(II)$.$(B)$ Phenol reacts with $Na_2Cr_2O_7 / H_2SO_4$ to form $p$-benzoquinone. This corresponds to product $(IV)$.$(C)$ Phenol reacts with $CHCl_3 + aq. NaOH$ followed by $H^+$ (Reimer-Tiemann reaction) to form salicylaldehyde. This corresponds to product $(I)$.$(D)$ Phenol reacts with $NaOH$,$CO_2$,and $H^+$ (Kolbe's reaction) to form salicylic acid. This corresponds to product $(III)$.Therefore,the correct matching is $A-II, B-IV, C-I, D-III$.

Column $(I)$	Column $(II)$
$(A)$ Kolbe's reaction	$(i)$ Salicylaldehyde
$(B)$ Reimer-Tiemann reaction	$(ii)$ Ethers
$(C)$ Williamson synthesis	$(iii)$ Ethanol
$(D)$ Fermentation	$(iv)$ Salicylic acid

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Match the reactions in Column $(I)$ with the products formed in Column $(II)$.

Column $(I)$ Column $(II)$

$(A)$ Kolbe's reaction $(i)$ Salicylaldehyde

$(B)$ Reimer-Tiemann reaction $(ii)$ Ethers

$(C)$ Williamson synthesis $(iii)$ Ethanol

$(D)$ Fermentation $(iv)$ Salicylic acid

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Match List-$I$ with List-$II$.Choose the correct answer from the options given below: