Medium
Match List-$I$ with List-$II$.
List-$I$ (Quantum Number) List-$II$ (Information provided) $A$. $m_l$ $I$. Shape of orbital $B$. $m_s$ $II$. Size of orbital $C$. $l$ $III$. Orientation of orbital $D$. $n$ $IV$. Orientation of spin of electron
Choose the correct answer from the options given below:
| List-$I$ (Quantum Number) | List-$II$ (Information provided) |
|---|---|
| $A$. $m_l$ | $I$. Shape of orbital |
| $B$. $m_s$ | $II$. Size of orbital |
| $C$. $l$ | $III$. Orientation of orbital |
| $D$. $n$ | $IV$. Orientation of spin of electron |
Choose the correct answer from the options given below:
- A$A-III, B-IV, C-I, D-II$
- B$A-III, B-IV, C-II, D-I$
- C$A-II, B-I, C-IV, D-III$
- D$A-I, B-III, C-II, D-IV$
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Similar Questions
Based on the quantum numbers, what will be the maximum number of elements in the sixth period of the periodic table?
Statement $A$: An orbital can accommodate a maximum of two electrons.
Reason $R$: Two electrons in an orbital produce opposite magnetic fields.
Reason $R$: Two electrons in an orbital produce opposite magnetic fields.
Medium
View SolutionThe incorrect set of quantum numbers $(n, l, m, s)$ for an electron in $3p$ orbital is
Match List-$I$ with List-$II$ :
List-$I$ (Quantum number) List-$II$ (Orbital) $a. n=2, \ell=1$ $i. 2s$ $b. n=3, \ell=2$ $ii. 3s$ $c. n=3, \ell=0$ $iii. 2p$ $d. n=2, \ell=0$ $iv. 3d$
Choose the correct answer from the options given below :
| List-$I$ (Quantum number) | List-$II$ (Orbital) |
| $a. n=2, \ell=1$ | $i. 2s$ |
| $b. n=3, \ell=2$ | $ii. 3s$ |
| $c. n=3, \ell=0$ | $iii. 2p$ |
| $d. n=2, \ell=0$ | $iv. 3d$ |
Choose the correct answer from the options given below :
MediumNEET 2022
View SolutionThe number of radial (spherical) nodes in a $4p$ orbital is $....$.
Difficult
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