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(C) The correct matching is as follows:- $A$. $RNA$ polymerase $III$ is responsible for the transcription of $snRNAs$,$tRNA$,and $5s$ $rRNA$. Thus,$A-

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$A-IV, B-III, C-I, D-II$

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(C) The correct matching is as follows:- $A$. $RNA$ polymerase $III$ is responsible for the transcription of $snRNAs$,$tRNA$,and $5s$ $rRNA$. Thus,$A-IV$.- $B$. The termination of transcription in prokaryotes is facilitated by the Rho factor. Thus,$B-III$.- $C$. Splicing of exons involves the removal of introns and joining of exons,a process performed by $snRNPs$ (small nuclear ribonucleoproteins). Thus,$C-I$.- $D$. The $TATA$ box is a specific $DNA$ sequence found in the promoter region of the transcription unit. Thus,$D-II$.Therefore,the correct sequence is $A-IV, B-III, C-I, D-II$.

List $I$	List $II$
$A$. $RNA$ polymerase $III$	$I$. snRNPs
$B$. Termination of transcription	$II$. Promoter
$C$. Splicing of exons	$III$. Rho factor
$D$. $TATA$ box	$IV$. snRNAs,tRNA

Match List $I$ with List $II$:

List $I$ List $II$

$A$. $RNA$ polymerase $III$ $I$. snRNPs

$B$. Termination of transcription $II$. Promoter

$C$. Splicing of exons $III$. Rho factor

$D$. $TATA$ box $IV$. snRNAs,tRNA

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Match List $I$ with List $II$: List $I$ List $II$ $A$. $RNA$ polymerase $III$ $I$. snRNPs $B$. Termination of transcription $II$. Promoter $C$. Splicing of exons $III$. Rho factor $D$. $TATA$ box $IV$. snRNAs,tRNA Choose the correct answer from the options given below: