Match List I with List II: (A). Inductive eff | vedclass

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Question

(A) Step $1$: Inductive effect is the permanent displacement of $\sigma$ electrons along a carbon chain due to the difference in electronegativity of

Vedclass · Accepted Answer

$(A) - (IV), (B) - (III), (C) - (I)$

Vedclass · Answer

(A) Step $1$: Inductive effect is the permanent displacement of $\sigma$ electrons along a carbon chain due to the difference in electronegativity of atoms or groups. Thus, $(A) - (IV)$.Step $2$: Hyper-conjugation involves the delocalization of $\sigma$ electrons of a $C-H$ bond of an alkyl group directly attached to an unsaturated system. Thus, $(B) - (III)$.Step $3$: Resonance effect involves the delocalization of $\pi$ electrons or lone pair electrons in a conjugated system. Thus, $(C) - (I)$.Step $4$: Combining these, we get $(A) - (IV), (B) - (III), (C) - (I)$. Therefore, the correct option is $A$.

$(A)$. Inductive effect	$(I)$. Delocalization of $\pi$ electrons
$(B)$. Hyper-conjugation	$(II)$. Displacement of $\pi$ electrons
$(C)$. Resonance effect	$(III)$. Delocalization of $\sigma$ electrons
	$(IV)$. Displacement of $\sigma$ electrons

Column $-I$	Column $-II$
$(i)$ $C_6H_5NH_2$	$(p)$ $-R$ effect
$(ii)$ $C_6H_5OH$	$(q)$ $+R$ effect
$(iii)$ $C_6H_5NO_2$	$(r)$ $+I$ effect
$(iv)$ $CH_3CH_2Cl$	$(s)$ $-I$ effect

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The correct order of stability for the following alkoxides is:
$(A)$ $CH_3CH(NO_2)O^-$
$(B)$ $CH_2=C(NO_2)O^-$
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Which one of the following orders is correct regarding the inductive effect of the substituents?

Match column $-I$ and column $-II$ with the correct electronic effect relation:

Column $-I$ Column $-II$

$(i)$ $C_6H_5NH_2$ $(p)$ $-R$ effect

$(ii)$ $C_6H_5OH$ $(q)$ $+R$ effect

$(iii)$ $C_6H_5NO_2$ $(r)$ $+I$ effect

$(iv)$ $CH_3CH_2Cl$ $(s)$ $-I$ effect

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