Match the chemical substances in Column-$I$ with the type of polymers/type of bonds in Column-$II$.
Column-$I$ Column-$II$ $A$. Cellulose $p$. Natural polymer $B$. Nylon-$6,6$ $q$. Synthetic polymer $C$. Protein $r$. Amide linkage $D$. Sucrose $s$. Glycoside linkage
| Column-$I$ | Column-$II$ |
| $A$. Cellulose | $p$. Natural polymer |
| $B$. Nylon-$6,6$ | $q$. Synthetic polymer |
| $C$. Protein | $r$. Amide linkage |
| $D$. Sucrose | $s$. Glycoside linkage |
- A$A$ $\rightarrow p, s; B$ $\rightarrow q, r; C$ $\rightarrow p, r; D$ $\rightarrow s$
- B$A$ $\rightarrow s, r; B$ $\rightarrow q, s; C$ $\rightarrow p, r; D$ $\rightarrow q$
- C$A$ $\rightarrow q, r; B$ $\rightarrow s, r; C$ $\rightarrow p, s; D$ $\rightarrow q$
- D$A$ $\rightarrow p, s; B$ $\rightarrow q, r; C$ $\rightarrow p, r; D$ $\rightarrow s$
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Similar Questions
Assertion : $1, 3-$ Butadiene is the monomer for natural rubber.
Reason : Natural rubber is formed through anionic addition polymerization.
Reason : Natural rubber is formed through anionic addition polymerization.
MediumAIIMS 2006
View SolutionAn organic compound $P$ with molecular formula $C_{9}H_{18}O_{2}$ decolorizes bromine water and also shows a positive iodoform test. $P$ on ozonolysis followed by treatment with $H_{2}O_{2}$ gives $Q$ and $R$. While compound $Q$ shows a positive iodoform test,compound $R$ does not. $Q$ and $R$ on oxidation with pyridinium chlorochromate $(PCC)$ followed by heating give $S$ and $T$,respectively. Both $S$ and $T$ show a positive iodoform test.
Complete copolymerization of $500$ moles of $Q$ and $500$ moles of $R$ gives one mole of a single acyclic copolymer $U$.
[Given,atomic mass: $H=1, C=12, O=16$ ]
$(1)$ Sum of the number of oxygen atoms in $S$ and $T$ is. . . . . .
$(2)$ The molecular weight of $U$ is
Give the answer for questions $(1)$ and $(2)$.
Complete copolymerization of $500$ moles of $Q$ and $500$ moles of $R$ gives one mole of a single acyclic copolymer $U$.
[Given,atomic mass: $H=1, C=12, O=16$ ]
$(1)$ Sum of the number of oxygen atoms in $S$ and $T$ is. . . . . .
$(2)$ The molecular weight of $U$ is
Give the answer for questions $(1)$ and $(2)$.
Match materials given in Column-$I$ with the polymers given in Column-$II$.
Column-$I$ Column-$II$ $A$. Natural rubber latex $i$. Nylon $B$. Wood laminates $ii$. Neoprene $C$. Ropes and fibres $iii$. Dacron $D$. Polyester fabric $iv$. Melamine formaldehyde resins $E$. Synthetic rubber $v$. Urea-formaldehyde resins $F$. Unbreakable crockery $vi$. cis-polyisoprene
| Column-$I$ | Column-$II$ |
| $A$. Natural rubber latex | $i$. Nylon |
| $B$. Wood laminates | $ii$. Neoprene |
| $C$. Ropes and fibres | $iii$. Dacron |
| $D$. Polyester fabric | $iv$. Melamine formaldehyde resins |
| $E$. Synthetic rubber | $v$. Urea-formaldehyde resins |
| $F$. Unbreakable crockery | $vi$. cis-polyisoprene |
Medium
View SolutionWhich of the following statements is correct for a spontaneous polymerization reaction?
Match the following:
List-$I$ List-$II$ $A$. $(CH_2-C(Cl)=CH-CH_2)_n$ $I$. Cross-linked network $B$. Nylon-$6,6$ $II$. Elastomer $C$. $HDP$ $III$. Fibre $D$. Melamine-formaldehyde $IV$. Ziegler-Natta catalyst
| List-$I$ | List-$II$ |
|---|---|
| $A$. $(CH_2-C(Cl)=CH-CH_2)_n$ | $I$. Cross-linked network |
| $B$. Nylon-$6,6$ | $II$. Elastomer |
| $C$. $HDP$ | $III$. Fibre |
| $D$. Melamine-formaldehyde | $IV$. Ziegler-Natta catalyst |
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