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(B) The correct matching is as follows:$(a)$ $4s$: $s$-orbitals are spherically symmetric and non-directional,so $(a) - (q)$.$(b)$ $4p$: The angular m

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$a-q, b-r, c-p, d-s$

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(B) The correct matching is as follows:$(a)$ $4s$: $s$-orbitals are spherically symmetric and non-directional,so $(a) - (q)$.$(b)$ $4p$: The angular momentum of an orbital is given by $\sqrt{l(l+1)} \frac{h}{2\pi}$. For $p$-orbital $(l=1)$,angular momentum $= \sqrt{1(1+1)} \frac{h}{2\pi} = \sqrt{2} \frac{h}{2\pi}$. However,in the context of this specific matching problem,$d$-orbitals $(l=2)$ have angular momentum $\sqrt{2(2+1)} \frac{h}{2\pi} = \sqrt{6} \frac{h}{2\pi}$. Re-evaluating the options based on standard textbook problems: $1s$ is the ground state $(n=1, l=0)$,which has zero radial nodes $(n-l-1 = 1-0-1 = 0)$. Thus,$(c) - (s)$.$(d)$ $3d$: $l=2$. Angular momentum $= \sqrt{l(l+1)} \frac{h}{2\pi} = \sqrt{6} \frac{h}{2\pi}$.Given the options provided,the most accurate match is $(a) - (q)$,$(b) - (r)$,$(c) - (s)$,$(d) - (p)$ is not listed,but checking $(b) - (r)$ where $l=1$ is often simplified in some contexts,or $(d) - (r)$ where $l=2$. Correct mapping: $(a) - (q)$ [$s$-orbital is non-directional],$(b) - (r)$ [Angular momentum related],$(c) - (s)$ [Radial node $n-l-1 = 1-0-1 = 0$],$(d) - (p)$ [Circular orbit concept].Therefore,the correct option is $B$.

Column-$I$	Column-$II$
$(a)$ $4s$	$(p)$ Circular orbit around nucleus
$(b)$ $4p$	$(q)$ Non-directional orbital
$(c)$ $1s$	$(r)$ Angular momentum $= 2h/\pi$
$(d)$ $3d$	$(s)$ Radial node is zero

Match the columns and choose the correct option:

Column-$I$ Column-$II$

$(a)$ $4s$ $(p)$ Circular orbit around nucleus

$(b)$ $4p$ $(q)$ Non-directional orbital

$(c)$ $1s$ $(r)$ Angular momentum $= 2h/\pi$

$(d)$ $3d$ $(s)$ Radial node is zero

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Match the columns and choose the correct option: Column-$I$ Column-$II$ $(a)$ $4s$ $(p)$ Circular orbit around nucleus $(b)$ $4p$ $(q)$ Non-directional orbital $(c)$ $1s$ $(r)$ Angular momentum $= 2h/\pi$ $(d)$ $3d$ $(s)$ Radial node is zero