Match the following column:
Column-$I$ (Reaction) Column-$II$ (Electrophile) $A$. $C_6H_6 + CH_3Cl \xrightarrow{AlCl_3} C_6H_5CH_3$ $P$. $CO_2$ $B$. $C_6H_5OH + CO_2 \xrightarrow[H^+]{NaOH} \text{Salicylic acid}$ $Q$. $:CCl_2$ $C$. $C_6H_5OH + CHCl_3 \xrightarrow{KOH} \text{Salicylaldehyde}$ $R$. $\stackrel{+}{C}H_3$ $D$. $C_6H_6 + SO_3 \xrightarrow{H_2SO_4} C_6H_5SO_3H$ $S$. $\stackrel{+}{S}O_3H$ $T$. $SO_3$
| Column-$I$ (Reaction) | Column-$II$ (Electrophile) |
| $A$. $C_6H_6 + CH_3Cl \xrightarrow{AlCl_3} C_6H_5CH_3$ | $P$. $CO_2$ |
| $B$. $C_6H_5OH + CO_2 \xrightarrow[H^+]{NaOH} \text{Salicylic acid}$ | $Q$. $:CCl_2$ |
| $C$. $C_6H_5OH + CHCl_3 \xrightarrow{KOH} \text{Salicylaldehyde}$ | $R$. $\stackrel{+}{C}H_3$ |
| $D$. $C_6H_6 + SO_3 \xrightarrow{H_2SO_4} C_6H_5SO_3H$ | $S$. $\stackrel{+}{S}O_3H$ |
| $T$. $SO_3$ |
- A$A-R, B-P, C-Q, D-S$
- B$A-R, B-P, C-Q, D-T$
- C$A-R, B-Q, C-P, D-T$
- D$A-P, B-R, C-Q, D-S$
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Match the compounds in Group-$I$ with their uses in Group-$II$. Find the correct match for Group-$I$ from Group-$II$.
Group-$I$ (Compound) Group-$II$ (Use) $A$. Alcohol $1$. Antiseptic $B$. Phenol $2$. Perfumes $C$. Ether $3$. Detergents $D$. Amine $4$. Dyes
| Group-$I$ (Compound) | Group-$II$ (Use) |
| $A$. Alcohol | $1$. Antiseptic |
| $B$. Phenol | $2$. Perfumes |
| $C$. Ether | $3$. Detergents |
| $D$. Amine | $4$. Dyes |
Medium
View SolutionProduct $(D)$ in the above reaction is:
Medium
View SolutionMatch the reactions given in Column-$I$ with the conditions given in Column-$II$.
Column-$I$ (Reaction) Column-$II$ (Condition) $(A)$ $CH_3-CH(OH)-CH_3 \rightarrow CH_3-CH=CH_2$ $(i)$ $20\% \ H_3PO_4, 358 \ K$ $(B)$ $CH_3-C(CH_3)_2-OH \rightarrow CH_3-C(CH_3)=CH_2$ (ii) $Cu, 573 \ K$ $(C)$ $CH_3CH_2OH \rightarrow CH_2=CH_2 + H_2O$ (iii) $85\% \ H_3PO_4, 440 \ K$ $(D)$ $R-CH(OH)-R' \rightarrow R-CO-R'$ (iv) $H_2SO_4, 443 \ K$
| Column-$I$ (Reaction) | Column-$II$ (Condition) |
|---|---|
| $(A)$ $CH_3-CH(OH)-CH_3 \rightarrow CH_3-CH=CH_2$ | $(i)$ $20\% \ H_3PO_4, 358 \ K$ |
| $(B)$ $CH_3-C(CH_3)_2-OH \rightarrow CH_3-C(CH_3)=CH_2$ | (ii) $Cu, 573 \ K$ |
| $(C)$ $CH_3CH_2OH \rightarrow CH_2=CH_2 + H_2O$ | (iii) $85\% \ H_3PO_4, 440 \ K$ |
| $(D)$ $R-CH(OH)-R' \rightarrow R-CO-R'$ | (iv) $H_2SO_4, 443 \ K$ |
Medium
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