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(A-II, B-I, C-IV, D-III) The correct matches are as follows:$A$. Natural rubber is a polymer of isoprene ($2$-methyl-$1,3$-butadiene). Thus, $A \right

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(A-II, B-I, C-IV, D-III) The correct matches are as follows:$A$. Natural rubber is a polymer of isoprene ($2$-methyl-$1,3$-butadiene). Thus, $A \rightarrow ii$.$B$. Cellulose is a polysaccharide consisting of a linear chain of $\beta(1-4)$ linked $\beta$-$D$-glucose units. Thus, $B \rightarrow i$.$C$. The monomer unit of Nylon-$6$ is caprolactam. Thus, $C \rightarrow iv$.$D$. Teflon is formed by the polymerization of tetrafluoroethylene monomer units: $n(CF_2=CF_2) \rightarrow -(CF_2-CF_2)_n-$. Thus, $D \rightarrow iii$.The correct matching is $A-ii, B-i, C-iv, D-iii$.

List-$I$	List-$II$
$A$. Natural rubber	$i$. $\beta$-glucose
$B$. Cellulose	$ii$. Isoprene
$C$. Nylon-$6$	$iii$. Tetrafluoroethylene
$D$. Teflon	$iv$. Caprolactam

Match the following items in List-$I$ with their corresponding monomer units in List-$II$.
List-$I$ List-$II$
$A$. Natural rubber $i$. $\beta$-glucose
$B$. Cellulose $ii$. Isoprene
$C$. Nylon-$6$ $iii$. Tetrafluoroethylene
$D$. Teflon $iv$. Caprolactam

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Match the following items in List-$I$ with their corresponding monomer units in List-$II$.List-$I$List-$II$$A$. Natural rubber$i$. $\beta$-glucose$B$. Cellulose$ii$. Isoprene$C$. Nylon-$6$$iii$. Tetrafluoroethylene$D$. Teflon$iv$. Caprolactam