Match the following molecules/ions in List-I | vedclass

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(A) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{V - M - C + A}{2}$,where $V$ is the numbe

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$A-III, B-IV, C-I, D-II$

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(A) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{V - M - C + A}{2}$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.$(A)$ For $XeF_2$: $V=8, M=2, C=0, A=0$. $	ext{Lone pairs} = \frac{8-2}{2} = 3$. Thus,$A-III$.$(B)$ For $XeO_3$: $V=8, M=0$ (Oxygen is divalent),$C=0, A=0$. $	ext{Lone pairs} = \frac{8-0}{2} = 4$ valence electrons involved in bonding,but since $O$ is divalent,$3$ double bonds use $6$ electrons,leaving $1$ lone pair. Thus,$B-IV$.$(C)$ For $XeF_4$: $V=8, M=4, C=0, A=0$. $	ext{Lone pairs} = \frac{8-4}{2} = 2$. Thus,$C-I$.$(D)$ For $PF_6^-$: $V=5, M=6, C=0, A=1$. $	ext{Lone pairs} = \frac{5-6+1}{2} = 0$. Thus,$D-II$.The correct matching is $A-III, B-IV, C-I, D-II$.

List-$I$ (molecule/ion)	List-$II$ (Number of lone pairs of electrons on the central atom)
$(A)$ $XeF_2$	$(I)$ $2$
$(B)$ $XeO_3$	$(II)$ $0$
$(C)$ $XeF_4$	$(III)$ $3$
$(D)$ $PF_6^-$	$(IV)$ $1$

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