Match the given ionisation constant values with the corresponding acids.
$A$. $HI$$(i)$ $3.2 \times 10^9$
$B$. $HF$$(ii)$ $3.5 \times 10^{-4}$
$C$. $HCl$$(iii)$ $1.3 \times 10^6$
$D$. $HBr$$(iv)$ $1.0 \times 10^9$

The correct match is:

  • A
    $A-(i), B-(ii), C-(iii), D-(iv)$
  • B
    $A-(ii), B-(iii), C-(iv), D-(i)$
  • C
    $A-(iv), B-(iii), C-(ii), D-(i)$
  • D
    $A-(ii), B-(i), C-(iii), D-(iv)$

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$A$. Phenol$I$. $1 \times 10^{-13}$
$B$. Benzoic acid$II$. $3.0 \times 10^{-8}$
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