Class 12ChemistryGeneral Principles and Processes of Isolation of ElementsMix Examples of General Principles and processes of Isolation of Elements
MediumMatch the items under List-$I$ with the compounds/elements from the List-$II$. Select the correct answer from the sets $(a), (b), (c)$ and $(d)$.
List-$I$ List-$II$ $(i)$ Explosive $(A)$ $NaN_3$ $(ii)$ Artificial gem $(B)$ $Fe_3O_4$ $(iii)$ Self reduction $(C)$ $Sn$ $(iv)$ Magnetic material $(D)$ $Al_2O_3$ $(E)$ $Pb(N_3)_2$ $(F)$ $Fe_2O_3$ $(G)$ $Cu$ $(H)$ $SiC$
| List-$I$ | List-$II$ |
|---|---|
| $(i)$ Explosive | $(A)$ $NaN_3$ |
| $(ii)$ Artificial gem | $(B)$ $Fe_3O_4$ |
| $(iii)$ Self reduction | $(C)$ $Sn$ |
| $(iv)$ Magnetic material | $(D)$ $Al_2O_3$ |
| $(E)$ $Pb(N_3)_2$ | |
| $(F)$ $Fe_2O_3$ | |
| $(G)$ $Cu$ | |
| $(H)$ $SiC$ |
- A$(i)-A, (ii)-D, (iii)-G, (iv)-B$
- B$(i)-A, (ii)-D, (iii)-G, (iv)-F$
- C$(i)-E, (ii)-D, (iii)-G, (iv)-B$
- D$(i)-E, (ii)-H, (iii)-C, (iv)-F$
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Match Column-$I$ with Column-$II$.
Column-$I$ Column-$II$ $P$. Nitriding $I$. Process of heating steel to redness and then cooling it very slowly $Q$. Annealing $II$. Process of heating steel in presence of $NH_3$ and producing hard coating of Iron Nitride on the surface of steel $R$. Tempering $III$. Process of heating steel to redness and then cooling it suddenly by plunging it into water or oil $S$. Quenching $IV$. Process of heating quenched steel to a temperature well below redness and then cooling it slowly
| Column-$I$ | Column-$II$ |
|---|---|
| $P$. Nitriding | $I$. Process of heating steel to redness and then cooling it very slowly |
| $Q$. Annealing | $II$. Process of heating steel in presence of $NH_3$ and producing hard coating of Iron Nitride on the surface of steel |
| $R$. Tempering | $III$. Process of heating steel to redness and then cooling it suddenly by plunging it into water or oil |
| $S$. Quenching | $IV$. Process of heating quenched steel to a temperature well below redness and then cooling it slowly |
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View SolutionSteel contains
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View SolutionMatch the following:
List-$I$ List-$II$ $A. Al_2O_3 + 2NaOH + 3H_2O \rightarrow 2Na[Al(OH)_4]$ $I. \text{Roasting}$ $B. Ni(CO)_4 \xrightarrow{230^{\circ}C} Ni + 4CO$ $II. \text{Calcination}$ $C. Fe_2O_3 \cdot 3H_2O \xrightarrow{\Delta} Fe_2O_3 + 3H_2O$ $III. \text{Vapour phase refining}$ $D. 2PbS + 3O_2 \rightarrow 2PbO + 2SO_2$ $IV. \text{Electrolysis}$ $V. \text{Leaching}$
The correct answer is:
| List-$I$ | List-$II$ |
| $A. Al_2O_3 + 2NaOH + 3H_2O \rightarrow 2Na[Al(OH)_4]$ | $I. \text{Roasting}$ |
| $B. Ni(CO)_4 \xrightarrow{230^{\circ}C} Ni + 4CO$ | $II. \text{Calcination}$ |
| $C. Fe_2O_3 \cdot 3H_2O \xrightarrow{\Delta} Fe_2O_3 + 3H_2O$ | $III. \text{Vapour phase refining}$ |
| $D. 2PbS + 3O_2 \rightarrow 2PbO + 2SO_2$ | $IV. \text{Electrolysis}$ |
| $V. \text{Leaching}$ |
The correct answer is:
Extraction of copper from copper pyrite $CuFeS_2$ involves:
$A$. Crushing followed by concentration of the ore by froth-flotation
$B$. Removal of iron as slag
$C$. Self-reduction step to produce 'blister copper' following evolution of $SO_2$
$D$. Refining of 'blister copper' by carbon reduction
$A$. Crushing followed by concentration of the ore by froth-flotation
$B$. Removal of iron as slag
$C$. Self-reduction step to produce 'blister copper' following evolution of $SO_2$
$D$. Refining of 'blister copper' by carbon reduction
Gun metal is an alloy of
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