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(A) According to $VSEPR$ theory:$1$. $PCl_3$: Central atom $P$ has $5$ valence electrons. It forms $3$ bonds with $Cl$ and has $1$ lone pair. Total el

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$A-III, B-V, C-II, D-I$

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(A) According to $VSEPR$ theory:$1$. $PCl_3$: Central atom $P$ has $5$ valence electrons. It forms $3$ bonds with $Cl$ and has $1$ lone pair. Total electron pairs = $4$ ($3$ bond pairs + $1$ lone pair),resulting in a Trigonal pyramidal geometry $(A-III)$.$2$. $BF_3$: Central atom $B$ has $3$ valence electrons. It forms $3$ bonds with $F$ and has $0$ lone pairs. Total electron pairs = $3$,resulting in a Trigonal planar geometry $(B-V)$.$3$. $ClF_3$: Central atom $Cl$ has $7$ valence electrons. It forms $3$ bonds with $F$ and has $2$ lone pairs. Total electron pairs = $5$,resulting in a $T$-shape geometry $(C-II)$.$4$. $XeF_4$: Central atom $Xe$ has $8$ valence electrons. It forms $4$ bonds with $F$ and has $2$ lone pairs. Total electron pairs = $6$,resulting in a Square planar geometry $(D-I)$.Therefore,the correct match is $A-III, B-V, C-II, D-I$.

List-$I$	List-$II$
$(A)$ $PCl_3$	$(I)$ Square planar
$(B)$ $BF_3$	$(II)$ $T$-shape
$(C)$ $ClF_3$	$(III)$ Trigonal pyramidal
$(D)$ $XeF_4$	$(IV)$ See-saw
	$(V)$ Trigonal planar

Match the molecules in List-$I$ with their correct geometries in List-$II$ according to $VSEPR$ theory:
List-$I$ List-$II$
$(A)$ $PCl_3$ $(I)$ Square planar
$(B)$ $BF_3$ $(II)$ $T$-shape
$(C)$ $ClF_3$ $(III)$ Trigonal pyramidal
$(D)$ $XeF_4$ $(IV)$ See-saw
$(V)$ Trigonal planar

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Match the molecules in List-$I$ with their correct geometries in List-$II$ according to $VSEPR$ theory:List-$I$List-$II$$(A)$ $PCl_3$$(I)$ Square planar$(B)$ $BF_3$$(II)$ $T$-shape$(C)$ $ClF_3$$(III)$ Trigonal pyramidal$(D)$ $XeF_4$$(IV)$ See-saw$(V)$ Trigonal planar