Match the process in Column-I with the enzyme | vedclass

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(B) The correct matches are as follows:$1$. $(A)$ $DNA$ replication: This process involves the synthesis of a new $DNA$ strand from a $DNA$ template,c

Vedclass · Accepted Answer

$A-(q), B-(s), C-(p), D-(r)$

Vedclass · Answer

(B) The correct matches are as follows:$1$. $(A)$ $DNA$ replication: This process involves the synthesis of a new $DNA$ strand from a $DNA$ template,catalyzed by the enzyme $(q)$ $DNA$ polymerase.$2$. $(B)$ Translation: This process involves the synthesis of proteins from mRNA. The enzyme $(s)$ Aminoacyl-tRNA synthetase is responsible for charging the tRNA with the appropriate amino acid.$3$. $(C)$ Transcription: This process involves the synthesis of $RNA$ from a $DNA$ template,catalyzed by the enzyme $(p)$ $RNA$ polymerase.$4$. $(D)$ Reverse transcription: This process involves the synthesis of $DNA$ from an $RNA$ template,catalyzed by the enzyme $(r)$ Reverse transcriptase.Therefore,the correct matching is $A-(q), B-(s), C-(p), D-(r)$.

Column-$I$	Column-$II$	Column-$III$
$(1) \ 1952$	$(a)$ Watson and Crick	$(i)$ Double helix model of $DNA$
$(2) \ 1928$	$(b)$ Friedrich Miescher	$(ii)$ Proof that $DNA$ is genetic material
$(3) \ 1869$	$(c)$ Griffith	$(iii)$ Nuclein
$(4) \ 1953$	$(d)$ Hershey and Chase	$(iv)$ Transforming principle

Column $X$	Column $Y$
$(1)$ Chromosome	$(P)$ Genetic code
$(2)$ $m-RNA$	$(Q)$ Gene
$(3)$ $t-RNA$	$(R)$ Ribosome
$(4)$ $r-RNA$	$(S)$ Anticodon

Similar Questions

Which one of the following pairs is not correctly matched?

Assertion : Histones are basic proteins of major importance in packaging of eukaryotic $DNA$. $DNA$ and histones comprise chromatin forming the bulk of eukaryotic chromosome.
Reason : Histones are of five major types $H_1, H_2A, H_2B, H_3$ and $H_4$.

The $T_4$ bacteriophage $rII$ mutant strain fails to lyse $E. coli$. However,when two strains $rII^X$ and $rII^Y$ are mixed,they lyse $E. coli$. What is the possible reason for this?

Select the correct match for $X$ and $Y$:
Column $X$ Column $Y$
$(1)$ Chromosome $(P)$ Genetic code
$(2)$ $m-RNA$ $(Q)$ Gene
$(3)$ $t-RNA$ $(R)$ Ribosome
$(4)$ $r-RNA$ $(S)$ Anticodon

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Column-$I$	Column-$II$
$(A)$ $DNA$ replication	$(p)$ $RNA$ polymerase
$(B)$ Translation	$(q)$ $DNA$ polymerase
$(C)$ Transcription	$(r)$ Reverse transcriptase
$(D)$ Reverse transcription	$(s)$ Aminoacyl synthetase