Match the ranges of the functions given in List-$I$ with those of the items given in List-$II$:
List-$I$List-$II$
$(I) \ 3 \sin^2 x + 4 \cos^2 x - 2$$(a) \ [\frac{1}{4}, 1]$
$(II) \ \cos^2 x + \sin^4 x$$(b) \ [-\frac{1}{4}, \frac{1}{4}]$
$(III) \ \sin^6 x + \cos^6 x$$(c) \ [1, 2]$
$(IV) \ \cos x \cos(\frac{2 \pi}{3} + x) \cos(\frac{2 \pi}{3} - x)$$(d) \ [\frac{3}{4}, 1]$
$(e) \ [0, 1]$

  • A
    $(I) \rightarrow (c), (II) \rightarrow (d), (III) \rightarrow (a), (IV) \rightarrow (b)$
  • B
    $(I) \rightarrow (c), (II) \rightarrow (a), (III) \rightarrow (d), (IV) \rightarrow (b)$
  • C
    $(I) \rightarrow (b), (II) \rightarrow (d), (III) \rightarrow (a), (IV) \rightarrow (e)$
  • D
    $(I) \rightarrow (b), (II) \rightarrow (e), (III) \rightarrow (d), (IV) \rightarrow (c)$

Explore More

Similar Questions

If the maximum value of $y = \frac{7 + 6 \tan x - \tan^2 x}{1 + \tan^2 x}$ is $\lambda$,then the value of $\log_{\sqrt{2}}(\lambda)$ is

Let $f(\theta) = (1 + \sin^2 \theta)(2 - \sin^2 \theta)$. Then, for all values of $\theta$:

If $A+B+C=\frac{\pi}{3}$,then $\sin \left(\frac{\pi-6A}{6}\right)+\sin \left(\frac{\pi-6B}{6}\right)+\sin C=$

The maximum value of $5 \cos \theta + 3 \cos \left( \theta + \frac{\pi}{3} \right) - 1$ is

If $\alpha+\beta=\frac{\pi}{2}$ and $\beta+\gamma=\alpha$,then $\tan \alpha$ equals

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo