Match the thermodynamic processes taking place in a system with the correct conditions. In the table: $\Delta Q$ is the heat supplied,$\Delta W$ is the work done and $\Delta U$ is change in internal energy of the system.
Process Condition $(I)$ Adiabatic $(A)$ $\Delta W = 0$ $(II)$ Isothermal $(B)$ $\Delta Q = 0$ $(III)$ Isochoric $(C)$ $\Delta U \neq 0, \Delta W \neq 0, \Delta Q \neq 0$ $(IV)$ Isobaric $(D)$ $\Delta U = 0$
| Process | Condition |
| $(I)$ Adiabatic | $(A)$ $\Delta W = 0$ |
| $(II)$ Isothermal | $(B)$ $\Delta Q = 0$ |
| $(III)$ Isochoric | $(C)$ $\Delta U \neq 0, \Delta W \neq 0, \Delta Q \neq 0$ |
| $(IV)$ Isobaric | $(D)$ $\Delta U = 0$ |
- A$I-B, II-D, III-A, IV-C$
- B$I-B, II-A, III-D, IV-C$
- C$I-A, II-A, III-B, IV-C$
- D$I-A, II-B, III-D, IV-D$
Explore More
Similar Questions
For one mole of a van der Waals gas,when $b = 0$ and $T = 300 \ K$,the plot of $PV$ versus $1/V$ is shown below. The value of the van der Waals constant $a \ (atm \ L^2 \ mol^{-2})$ is:
In the following combinations of logic gates,the outputs of $A, B$ and $C$ are respectively:
Two identical balls $A$ and $B$ are released from the positions shown in the figure. They collide elastically on the horizontal portion $MN$. The ratio of the heights attained by $A$ and $B$ after the collision will be: (neglect friction)
If the lines $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}$ and $\frac{x-3}{1}=\frac{y-k}{2}=\frac{z}{1}$ intersect,then the value of $k$ is:
What is the size of $Wolffia$ $globosa$?
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo