Maximum bond angle at nitrogen is present in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The bond angles are determined by the hybridization and the presence of lone pairs or unpaired electrons on the central nitrogen atom:$1.$ $NO_{2}

Vedclass · Accepted Answer

$NO_{2}^{+}$

Vedclass · Answer

(A) The bond angles are determined by the hybridization and the presence of lone pairs or unpaired electrons on the central nitrogen atom:$1.$ $NO_{2}^{+}$: Nitrogen is $sp$ hybridized,resulting in a linear geometry with a bond angle of $180^{\circ}$.$2.$ $NO_{3}^{-}$: Nitrogen is $sp^{2}$ hybridized,resulting in a trigonal planar geometry with a bond angle of $120^{\circ}$.$3.$ $NO_{2}$: Nitrogen is $sp^{2}$ hybridized with one unpaired electron,resulting in a bent shape with a bond angle of approximately $134^{\circ}$.$4.$ $NO_{2}^{-}$: Nitrogen is $sp^{2}$ hybridized with one lone pair,resulting in a bent shape with a bond angle of approximately $115^{\circ}$.Therefore,the maximum bond angle is in $NO_{2}^{+}$.

Maximum bond angle at nitrogen is present in which of the following?

Similar Questions

According to $VSEPR$ theory,

How will you account for the $104.5^{\circ}$ bond angle in water?

The bond angle in $NF_{3}$ $(102.3^{\circ})$ is smaller than $NH_{3}$ $(107.2^{\circ})$. This is because of

Which of the following molecules has a planar structure?

$S +$ Conc. $H_2SO_4 \longrightarrow X + Y$
Here $X$ is a gas and $Y$ is a liquid and both are triatomic molecules. The number of electron lone pairs present on the central atoms of $X$ and $Y$ are respectively.

Vedclass Test Series

Exam Paper Generator

Online Exam Module