Maximum enthalpy change is associated with wh | vedclass

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Question

(C) The enthalpy change for the reaction $M_{(g)} + X_{(g)} 	o M^{+}_{(g)} + X^{-}_{(g)}$ is given by $\Delta H = IE - EA$,where $IE$ is the Ionizati

Vedclass · Accepted Answer

$Li_{(g)} + Br_{(g)} 	o Li^{+}_{(g)} + Br^{-}_{(g)}$

Vedclass · Answer

(C) The enthalpy change for the reaction $M_{(g)} + X_{(g)} 	o M^{+}_{(g)} + X^{-}_{(g)}$ is given by $\Delta H = IE - EA$,where $IE$ is the Ionization Energy of the metal and $EA$ is the Electron Affinity of the non-metal.To maximize $\Delta H$,we need the highest $IE$ and the lowest $EA$.$IE$ values: $Li > Na$ (since $Li$ is smaller than $Na$).$EA$ values: $Cl > Br$ (since $Cl$ is smaller than $Br$,it has a more negative electron affinity,meaning a higher magnitude of energy release).Therefore,the reaction with the highest $IE$ $(Li)$ and the lowest $EA$ magnitude $(Br)$ will result in the maximum enthalpy change.Thus,$Li_{(g)} + Br_{(g)} 	o Li^{+}_{(g)} + Br^{-}_{(g)}$ has the maximum enthalpy change.

Maximum enthalpy change is associated with which of the following reactions?

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