Maximum oxidation state is present in

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(C) To find the maximum oxidation state,we calculate the oxidation number of the central metal atom in each species:$(a)$ In $MnO_2$: $x + 2(-2) = 0 \

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$MnO_4^-$

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(C) To find the maximum oxidation state,we calculate the oxidation number of the central metal atom in each species:$(a)$ In $MnO_2$: $x + 2(-2) = 0 \Rightarrow x = +4$$(b)$ In $MnO$: $x + (-2) = 0 \Rightarrow x = +2$$(c)$ In $MnO_4^-$: $x + 4(-2) = -1$ $\Rightarrow x - 8 = -1$ $\Rightarrow x = +7$$(d)$ In $[Fe(CN)_6]^{4-}$: $x + 6(-1) = -4$ $\Rightarrow x - 6 = -4$ $\Rightarrow x = +2$Comparing the values,the maximum oxidation state is $+7$,which is present in $MnO_4^-$.

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