Maximum unpaired electrons are present in

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Question

(A) The electronic configuration of $O_2$ ($16$ electrons) is: $KK (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2pz)^2 (\pi 2px)^2 (\pi 2py)^2 (\pi^* 2px)^1

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$O_2$

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(A) The electronic configuration of $O_2$ ($16$ electrons) is: $KK (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2pz)^2 (\pi 2px)^2 (\pi 2py)^2 (\pi^* 2px)^1 (\pi^* 2py)^1$. It has $2$ unpaired electrons.The electronic configuration of $O_2^+$ ($15$ electrons) is: $KK (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2pz)^2 (\pi 2px)^2 (\pi 2py)^2 (\pi^* 2px)^1$. It has $1$ unpaired electron.The electronic configuration of $O_2^-$ ($17$ electrons) is: $KK (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2pz)^2 (\pi 2px)^2 (\pi 2py)^2 (\pi^* 2px)^2 (\pi^* 2py)^1$. It has $1$ unpaired electron.The electronic configuration of $O_2^{2-}$ ($18$ electrons) is: $KK (\sigma 2s)^2 (\sigma^* 2s)^2 (\sigma 2pz)^2 (\pi 2px)^2 (\pi 2py)^2 (\pi^* 2px)^2 (\pi^* 2py)^2$. It has $0$ unpaired electrons.Thus,$O_2$ has the maximum number of unpaired electrons.

List-$I$	List-$II$
$(a)$ $Ne_2$	$(i)$ $1$
$(b)$ $N_2$	$(ii)$ $2$
$(c)$ $F_2$	$(iii)$ $0$
$(d)$ $O_2$	$(iv)$ $3$

Similar Questions

Answer the following questions:
$(i)$ Give the molecular orbitals and their types formed by $LCAO$ from $2s, 2p_{x}, 2p_{y}$ and $2p_{z}$ atomic orbitals.
$(ii)$ Provide the energy order of molecular orbitals for $Li_{2}, Be_{2}, C_{2}, N_{2}, O_{2}$ and $F_{2}$.

Assertion : $B_2$ molecule is diamagnetic. Reason : The highest occupied molecular orbital is of $\sigma$ type.

What is the difference in the $MO$ energy level diagram for diatomic molecules from $Li_2$ to $N_2$ compared to those from $O_2$ to $Ne_2$?

Match List-$I$ with List-$II$ based on the bond order of the molecules.

List-$I$ List-$II$

$(a)$ $Ne_2$ $(i)$ $1$

$(b)$ $N_2$ $(ii)$ $2$

$(c)$ $F_2$ $(iii)$ $0$

$(d)$ $O_2$ $(iv)$ $3$

Choose the correct answer from the options given below:

What is the bond order of $B_{2}$ molecule?

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