Milk and water are mixed in vessel A in the r | vedclass

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(A) In vessel $A$,the fraction of milk is $\frac{5}{7}$.In vessel $B$,the fraction of milk is $\frac{8}{13}$.The required fraction of milk in the fina

Vedclass · Accepted Answer

$7:2$

Vedclass · Answer

(A) In vessel $A$,the fraction of milk is $\frac{5}{7}$.In vessel $B$,the fraction of milk is $\frac{8}{13}$.The required fraction of milk in the final mixture is $\frac{9}{13}$.Using the rule of alligation:Difference for vessel $A = |\frac{8}{13} - \frac{9}{13}| = \frac{1}{13}$.Difference for vessel $B = |\frac{5}{7} - \frac{9}{13}| = |\frac{65 - 63}{91}| = \frac{2}{91}$.Required ratio of quantities from vessel $A$ and vessel $B = \frac{1}{13} : \frac{2}{91}$.To simplify,multiply both sides by $91$: $(\frac{1}{13} 	imes 91) : (\frac{2}{91} 	imes 91) = 7 : 2$.

Milk and water are mixed in vessel $A$ in the ratio of $5:2$ and in vessel $B$ in the ratio of $8:5$. In what ratio should quantities be taken from the two vessels so as to form a mixture in which milk and water will be in the ratio of $9:4$?

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