Minimum thickness of a mica sheet having $\mu = 3/2$ which should be placed in front of one of the slits in $YDSE$ is required to reduce the intensity at the centre of the screen to half of the maximum intensity is-

  • A
    $\lambda /4$
  • B
    $\lambda /8$
  • C
    $\lambda /2$
  • D
    $\lambda /3$

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What happens to the fringe width in Young's double-slit experiment if it is performed in glycerine instead of air?

The fringe width in a $YDSE$ pattern is $2.4 \times 10^{-4} \, m$ when red light of wavelength $6400 \, \mathring{A}$ is used. How much will it change if blue light of wavelength $4000 \, \mathring{A}$ is used?

In a Young's double slit experiment,the slit separation $d$ is $0.3 \text{ mm}$ and the screen distance $D$ is $1 \text{ m}$. $A$ parallel beam of light of wavelength $600 \text{ nm}$ is incident on the slits at angle $\alpha$ as shown in the figure. On the screen,the point $O$ is equidistant from the slits and the distance $PO$ is $11.0 \text{ mm}$. Which of the following statement$(s)$ is/are correct?

In $Y.D.S.E$, two slits are made $1 \, mm$ apart and the screen is placed $1 \, m$ away. The fringe separation when light of wavelength $500 \, nm$ is used is:

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In a certain region of the screen, the number of fringes formed is observed to be $8$ in Young's double slit experiment when light of wavelength $6600 \text{ Å}$ is used. If light of wavelength $4400 \text{ Å}$ is used, the number of fringes observed in the same region of the screen will be:

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