Mohan walks from Tilak Nagar to Moti Nagar an | vedclass

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Question

(D) Let the distance between Tilak Nagar and Moti Nagar be $d \, km$.In the first case,the total time taken is $T_1 = \frac{d}{3.5} + \frac{d}{3.5} =

Vedclass · Accepted Answer

none of these

Vedclass · Answer

(D) Let the distance between Tilak Nagar and Moti Nagar be $d \, km$.In the first case,the total time taken is $T_1 = \frac{d}{3.5} + \frac{d}{3.5} = \frac{2d}{3.5} = \frac{4d}{7} \, hours$.In the second case,the total time taken is $T_2 = \frac{d}{3} + \frac{d}{4} = \frac{4d + 3d}{12} = \frac{7d}{12} \, hours$.Given that the difference in time is $10 \, minutes = \frac{10}{60} = \frac{1}{6} \, hours$.So,$T_2 - T_1 = \frac{1}{6}$.$\frac{7d}{12} - \frac{4d}{7} = \frac{1}{6}$.Taking $LCM$ of $12$ and $7$ as $84$:$\frac{49d - 48d}{84} = \frac{1}{6}$.$\frac{d}{84} = \frac{1}{6}$.$d = \frac{84}{6} = 14 \, km$.Since $14 \, km$ is not among the options,the correct answer is $D$ (none of these).

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