Mohr salt is prepared from an equimolar solution of:
- A$FeSO_4 \cdot 7 H_2O$ and $K_2SO_4$
- B$FeSO_4 \cdot 7 H_2O$ and $(NH_4)_2SO_4$
- C$CuSO_4 \cdot 5 H_2O$ and $K_2SO_4$
- D$CuSO_4 \cdot 5 H_2O$ and $(NH_4)_2SO_4$
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