Molar conductances of $BaCl_2, H_2SO_4$ and $HCl$ at infinite dilutions are $x_1, x_2$ and $x_3$ respectively. Equivalent conductance of $BaSO_4$ at infinite dilution will be

  • A
    $(x_1 + x_2 - 2x_3) / 2$
  • B
    $x_1 + x_2 - 2x_3$
  • C
    $(x_1 + x_2 - x_3) / 2$
  • D
    $(x_1 - x_2 - x_3) / 2$

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$A$ conductivity cell is filled with $0.01 \ M \ KCl$ and gives a resistance of $484 \ \Omega$. The conductivity of the solution is $0.00141 \ \Omega^{-1} \ cm^{-1}$ at $25^{\circ}C$. What is the cell constant (in $cm^{-1}$)?

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Resistance of $0.2 \, M$ solution of an electrolyte is $50 \, \Omega$. The specific conductance of the solution is $1.4 \, S \, m^{-1}$. The resistance of $0.5 \, M$ solution of the same electrolyte is $280 \, \Omega$. The molar conductivity of $0.5 \, M$ solution of the electrolyte in $S \, m^2 \, mol^{-1}$ is:

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