Most acidic among the given compounds is:

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(D) The basicity of lanthanoid hydroxides $Ln(OH)_3$ decreases as the ionic radius of the $Ln^{3+}$ ion decreases due to lanthanoid contraction.As we

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$Er(OH)_3$

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(D) The basicity of lanthanoid hydroxides $Ln(OH)_3$ decreases as the ionic radius of the $Ln^{3+}$ ion decreases due to lanthanoid contraction.As we move from $Pr$ to $Er$ in the lanthanoid series,the ionic radius decreases $(Pr^{3+} > Sm^{3+} > Gd^{3+} > Er^{3+})$.Therefore,the basicity order is $Pr(OH)_3 > Sm(OH)_3 > Gd(OH)_3 > Er(OH)_3$.Since acidity is inversely proportional to basicity,the most acidic compound is the one with the smallest ionic radius,which is $Er(OH)_3$.

Similar Questions

What is the effect of lanthanoid contraction in the lanthanoid series of elements?

Which of the following elements shows the greatest similarity to the lanthanoids?

The correct statement is

Lanthanoid ions with $4f^7$ configuration are :
$A$. $Eu^{2+}$
$B$. $Gd^{3+}$
$C$. $Eu^{3+}$
$D$. $Tb^{3+}$
$E$. $Sm^{2+}$
Choose the correct answer from the options given below :

Which of the following elements can form compounds in $+3$ to $+7$ oxidation states?

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