The most basic 'N' atom in the following mole | vedclass

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(D) To determine the most basic nitrogen atom,we analyze the availability of the lone pair on each nitrogen atom:$1$. Nitrogen at position $A$ is part

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$D$

Vedclass · Answer

(D) To determine the most basic nitrogen atom,we analyze the availability of the lone pair on each nitrogen atom:$1$. Nitrogen at position $A$ is part of an aromatic pyridine-like ring. Its lone pair is in an $sp^2$ orbital perpendicular to the $\pi$-system,making it available for protonation.$2$. Nitrogen at position $B$ is an aniline-type amine. Its lone pair is delocalized into the aromatic ring,reducing its basicity.$3$. Nitrogen at position $C$ is an amide nitrogen. Its lone pair is delocalized into the adjacent carbonyl group $(C=O)$,making it non-basic.$4$. Nitrogen at position $D$ is a secondary aliphatic amine in a saturated piperidine ring. Its lone pair is in an $sp^3$ orbital and is not involved in resonance or delocalization. Aliphatic amines are generally more basic than aromatic amines or pyridine-like nitrogens.Therefore,the nitrogen at position $D$ is the most basic.

The most basic $'N'$ atom in the following molecule is:

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