Mr. Mani invested an amount of ₹ 12000 at a s | vedclass

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(A) Let the second amount invested be $P_{2}$.Given: $P_{1} = ₹ 12000$,$R_{1} = 10 \%$,$R_{2} = 20 \%$,and the effective rate of interest $R = 14 \%$.

Vedclass · Accepted Answer

$20000$

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(A) Let the second amount invested be $P_{2}$.Given: $P_{1} = ₹ 12000$,$R_{1} = 10 \%$,$R_{2} = 20 \%$,and the effective rate of interest $R = 14 \%$.The formula for the weighted average rate of interest is $R = \frac{P_{1}R_{1} + P_{2}R_{2}}{P_{1} + P_{2}}$.Substituting the values: $14 = \frac{12000 	imes 10 + P_{2} 	imes 20}{12000 + P_{2}}$.$14(12000 + P_{2}) = 120000 + 20P_{2}$.$168000 + 14P_{2} = 120000 + 20P_{2}$.$6P_{2} = 48000$.$P_{2} = ₹ 8000$.Total amount invested $= P_{1} + P_{2} = 12000 + 8000 = ₹ 20000$.

Mr. Mani invested an amount of ₹ $12000$ at a simple interest rate of $10 \%$ $p.a.$ and another amount at a simple interest rate of $20 \%$ $p.a.$. The total interest earned at the end of one year on the total amount invested was $14 \%$ $p.a.$. Find the total amount (in ₹) invested.

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