Name an element from Group $2$ which forms an amphoteric oxide and a water soluble sulphate.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(BERYLLIUM) Beryllium $(Be)$ is the element from Group $2$ that forms an amphoteric oxide,$BeO$,and a water-soluble sulphate,$BeSO_{4}$.
$BeO$ reacts with both acids and bases:
$BeO + 2HCl \rightarrow BeCl_{2} + H_{2}O$
$BeO + 2NaOH + H_{2}O \rightarrow Na_{2}[Be(OH)_{4}]$
$BeSO_{4}$ is soluble in water because its high hydration energy compensates for its lattice energy.

Explore More

Similar Questions

Which of the following hydroxides is insoluble in water?

The compound formed when gypsum is dissolved in aqueous ammonium sulphate solution is:

Which ion has the maximum complex-forming tendency?

Which of the following ions has a higher hydration enthalpy than the $Mg^{2+}$ ion?

In context with beryllium,which one of the following statements is incorrect?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo