Natural glucose is termed D-glucose because | vedclass

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(C) In the Fischer projection of monosaccharides,the $D$ or $L$ configuration is determined by the position of the $-OH$ group on the chiral carbon at

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$-OH$ on the fifth carbon is on the right side in Fischer projection

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(C) In the Fischer projection of monosaccharides,the $D$ or $L$ configuration is determined by the position of the $-OH$ group on the chiral carbon atom furthest from the carbonyl group (the highest numbered chiral carbon).For glucose,the chiral carbon furthest from the aldehyde group is the $C-5$ carbon.In $D$-glucose,the $-OH$ group on the $C-5$ carbon is on the right side in the Fischer projection.Therefore,the correct option is $C$.

Natural glucose is termed $D$-glucose because

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