Nitric oxide reacts with H_2 according to the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a general reaction $aA + bB \rightarrow cC + dD$,the rate of reaction is given by: Rate $= -\frac{1}{a} \frac{d[A]}{dt} = -\frac{1}{b} \frac{d

Vedclass · Accepted Answer

$-\frac{d[NO]}{dt} = \frac{d[H_2O]}{dt}$

Vedclass · Answer

(B) For a general reaction $aA + bB \rightarrow cC + dD$,the rate of reaction is given by: Rate $= -\frac{1}{a} \frac{d[A]}{dt} = -\frac{1}{b} \frac{d[B]}{dt} = \frac{1}{c} \frac{d[C]}{dt} = \frac{1}{d} \frac{d[D]}{dt}$. For the given reaction $2 NO_{(g)} + 2 H_{2(g)} \rightarrow N_{2(g)} + 2 H_2O_{(g)}$,the rate expression is: Rate $= -\frac{1}{2} \frac{d[NO]}{dt} = -\frac{1}{2} \frac{d[H_2]}{dt} = \frac{d[N_2]}{dt} = \frac{1}{2} \frac{d[H_2O]}{dt}$. Comparing the terms for $NO$ and $H_2O$: $-\frac{1}{2} \frac{d[NO]}{dt} = \frac{1}{2} \frac{d[H_2O]}{dt}$. Multiplying both sides by $2$,we get: $-\frac{d[NO]}{dt} = \frac{d[H_2O]}{dt}$.

Nitric oxide reacts with $H_2$ according to the reaction,$2 NO_{(g)} + 2 H_{2(g)} \rightarrow N_{2(g)} + 2 H_2O_{(g)}$. Identify the correct relationship among the following.

Similar Questions

Which one of the following equations is correct for the reaction $N_{2(g)} + 3H_{2(g)} \longrightarrow 2NH_{3(g)}$?

Consider the reaction given below:
$A + 2 B \longrightarrow 3 C + 2 D$.
If the rate of disappearance of $B$ is $x \times 10^{-2} \ mol \ L^{-1} \ s^{-1}$,the ratio of the rate of reaction and the rate of appearance of $C$ is:

Mention the factors that affect the rate of a chemical reaction.

For the reaction,$N_2 + 3H_2 \rightarrow 2NH_3,$ if $\frac{d[NH_3]}{dt} = 2 \times 10^{-4} \ mol \ L^{-1} \ s^{-1},$ the value of $-\frac{d[H_2]}{dt}$ would be .................. $mol \ L^{-1} \ s^{-1}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module