Nitrobenzene can be prepared from benzene by | vedclass

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(B) In the nitration of benzene,the reaction between conc. $HNO_3$ and conc. $H_2SO_4$ occurs as follows: $HNO_3 + H_2SO_4 \rightleftharpoons H_2NO_3^

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(B) In the nitration of benzene,the reaction between conc. $HNO_3$ and conc. $H_2SO_4$ occurs as follows: $HNO_3 + H_2SO_4 \rightleftharpoons H_2NO_3^+ + HSO_4^-$$H_2NO_3^+ \rightleftharpoons H_2O + NO_2^+$Here,$H_2SO_4$ is a stronger acid than $HNO_3$,so it protonates $HNO_3$. Thus,$HNO_3$ acts as a base in the presence of conc. $H_2SO_4$ to generate the electrophile $NO_2^+$.

Nitrobenzene can be prepared from benzene by using a mixture of conc. $HNO_3$ and conc. $H_2SO_4$. In the nitrating mixture,$HNO_3$ acts as a

Similar Questions

Assertion : Nitrating mixture used for carrying out nitration of benzene consists of conc. $HNO_3 +$ conc. $H_2SO_4$.
Reason : In presence of $H_2SO_4$,$HNO_3$ acts as a base and produces $NO_2^+$ ions.

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