Nitrobenzene gives N-phenylhydroxylamine by | vedclass

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Question

(D) The reduction of nitrobenzene to $N$-phenylhydroxylamine is a selective reduction process. When nitrobenzene is treated with a neutral reducing ag

Vedclass · Accepted Answer

$Zn/NH_4Cl$

Vedclass · Answer

(D) The reduction of nitrobenzene to $N$-phenylhydroxylamine is a selective reduction process. When nitrobenzene is treated with a neutral reducing agent like $Zn/NH_4Cl$,it undergoes partial reduction to form $N$-phenylhydroxylamine $(C_6H_5NHOH)$. Other reagents like $Sn/HCl$ or $H_2/Pd-C$ typically reduce nitrobenzene completely to aniline $(C_6H_5NH_2)$,while $Zn/NaOH$ can lead to different products like azoxybenzene,azobenzene,or hydrazobenzene depending on conditions. Therefore,the correct reagent is $Zn/NH_4Cl$.

Nitrobenzene gives $N$-phenylhydroxylamine by

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