A normal aluminium electrode coupled with a n | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The standard cell potential is given by the formula: $E_{cell}^{o} = E_{cathode}^{o} - E_{anode}^{o}$.Since the aluminium electrode is coupled wit

Vedclass · Accepted Answer

$-1.66$

Vedclass · Answer

(A) The standard cell potential is given by the formula: $E_{cell}^{o} = E_{cathode}^{o} - E_{anode}^{o}$.Since the aluminium electrode is coupled with a standard hydrogen electrode $(SHE)$ and the $emf$ is $1.66 \ V$,aluminium acts as the anode because it is more reactive than hydrogen.Therefore,$E_{cell}^{o} = E_{H^{+}/H_2}^{o} - E_{Al^{3+}/Al}^{o}$.Substituting the values: $1.66 \ V = 0.00 \ V - E_{Al^{3+}/Al}^{o}$.Thus,$E_{Al^{3+}/Al}^{o} = -1.66 \ V$.

Element	$M^{3+}/M$	$M^{+}/M$
$Al$	$-1.66$	$+0.55$
$Tl$	$+1.26$	$-0.34$

$A$ normal aluminium electrode coupled with a normal hydrogen electrode gives an $emf$ of $1.66 \ V$. The standard electrode potential of aluminium is ............ $V$.

Similar Questions

Which one of the following metals cannot evolve $H_2$ from acids,$H_2O$,or from its compounds?

Consider the following standard electrode potentials ($E^0$ in volts) in aqueous solution. Based on this data,which of the following statements is correct?
Element $M^{3+}/M$ $M^{+}/M$
$Al$ $-1.66$ $+0.55$
$Tl$ $+1.26$ $-0.34$

What is electrode potential?

$A$ standard hydrogen electrode has zero electrode potential because

If the electrode potential of $Zn^{2+} | Zn$ is $-0.76 \, V$ and the potential of $Cu^{2+} | Cu$ is $0.34 \, V$,what will be the $EMF$ of the cell formed by both electrodes in $V$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module