Nuclear energy is based on the conversion of

  • A
    Protons into neutrons
  • B
    Mass into energy
  • C
    Neutrons into protons
  • D
    Uranium into radium

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The calculated mass of ${}_{20}Ca^{40}$ is $40.328 \ u$. It releases $306.3 \ MeV$ energy in a nuclear process. Its isotopic mass is

If the binding energy per nucleon of $_1H^2$ is $x$ and that of $_2He^4$ is $7x$,then the ratio of the energy liberated in the reaction $_1H^2 + _1H^2 \to _2He^4$ to the binding energy per nucleon of $_1H^2$ is:

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View Solution

Assertion : Nuclear binding energy per nucleon is in the order $_4^9Be > \,_3^7Li > \,_2^4He$.
Reason : Binding energy per nucleon increases linearly with the difference in the number of neutrons and protons.

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