Number of sigma and pi bonds in benzophenone | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The chemical formula of benzophenone is $(C_6H_5)_2CO$.In the structure,there are two phenyl rings attached to a carbonyl group $(C=O)$.Each pheny

Vedclass · Accepted Answer

$25, 7$

Vedclass · Answer

(D) The chemical formula of benzophenone is $(C_6H_5)_2CO$.In the structure,there are two phenyl rings attached to a carbonyl group $(C=O)$.Each phenyl ring $(C_6H_5)$ contains $6$ $C-C$ bonds (including $3$ double bonds) and $5$ $C-H$ bonds.Total $\sigma$ bonds in two phenyl rings = $2 	imes (6 + 5) = 22$.There are $2$ $C-C$ single bonds connecting the carbonyl carbon to the phenyl rings.There is $1$ $C-O$ $\sigma$ bond in the carbonyl group.Total $\sigma$ bonds = $22 + 2 + 1 = 25$.Total $\pi$ bonds = $2 	imes 3$ (from two benzene rings) + $1$ (from $C=O$ bond) = $6 + 1 = 7$.Thus,there are $25$ $\sigma$ bonds and $7$ $\pi$ bonds.

Number of $\sigma$ and $\pi$ bonds in benzophenone is

Similar Questions

What is the first intermediate formed during the reduction of carbonyl compounds by $H_2NNH_2$ and $KOH$?

Reagents to carry out the above conversion,$P$,$Q$,$R$ respectively are:

Identify $A, B$,and $C$ in the following reactions:
Isopropyl chloride $\xrightarrow{NaOH} A$ $\xrightarrow{Cu/573 \ K} B$ $\xrightarrow{NaOI} C + \text{Iodoform}$

Tischenko reaction is a modification of

Which of the following can be used to differentiate pentan$-2-$one and pentan$-3-$one?

Vedclass Test Series

Exam Paper Generator

Online Exam Module