Number of colourless lanthanoid ions among th | vedclass

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(B) The colour of lanthanoid ions depends on the presence of unpaired $f$-electrons ($f-f$ transitions).Electronic configurations of the given ions ar

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$2$

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(B) The colour of lanthanoid ions depends on the presence of unpaired $f$-electrons ($f-f$ transitions).Electronic configurations of the given ions are:$La^{3+} = [Xe] 4f^0$ (No unpaired electrons)$Nd^{3+} = [Xe] 4f^3$ ($3$ unpaired electrons)$Sm^{3+} = [Xe] 4f^5$ ($5$ unpaired electrons)$Eu^{3+} = [Xe] 4f^6$ ($6$ unpaired electrons)$Lu^{3+} = [Xe] 4f^{14}$ (No unpaired electrons)Ions with $f^0$ or $f^{14}$ configurations are colourless because they lack unpaired electrons for $f-f$ transitions.Thus,$La^{3+}$ and $Lu^{3+}$ are colourless.The total number of colourless ions is $2$.

Number of colourless lanthanoid ions among the following is . . . . .
$Eu^{3+}, Lu^{3+}, Nd^{3+}, La^{3+}, Sm^{3+}$

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Number of colourless lanthanoid ions among the following is . . . . .$Eu^{3+}, Lu^{3+}, Nd^{3+}, La^{3+}, Sm^{3+}$